snapshot of treesome.js before deletion

This commit is contained in:
ansuz 2016-02-19 14:07:16 +01:00
parent 8ead5ca129
commit 1beb3f5355

View file

@ -1,9 +1,10 @@
define([], function () {
var tree = {};
tree.some = function (branch, predicate) {
// take the index of the last element in the current branch
var last = branch.childElementCount - 1;
// FIXME this isn't being used
var someElement = tree.some = function (root, predicate) {
// take the index of the last element in the current root
var last = root.childElementCount - 1;
// it might be a leaf node
if (last < 0) { return false; }
@ -14,12 +15,12 @@ define([], function () {
// check the node's children (depth first)
// if the predicate tests true, return true
if (tree.some(branch.children[last], predicate)) {
if (tree.some(root.children[last], predicate)) {
return true;
} // otherwise none of the nodes inside it matched.
// check the node itself
if (predicate(branch.children[last], last)) {
if (predicate(root.children[last], last)) {
return true;
}
last--;
@ -27,9 +28,10 @@ define([], function () {
return false;
};
tree.someIncludingText = function (branch, predicate) {
// take the index of the last element in the current branch
var last = branch.childNodes.length - 1;
// FIXME this isn't being used
var someText = tree.someIncludingText = function (root, predicate) {
// take the index of the last element in the current root
var last = root.childNodes.length - 1;
// it might be a leaf node
if (last < 0) { return false; }
@ -40,12 +42,12 @@ define([], function () {
// check the node's children (depth first)
// if the predicate tests true, return true
if (tree.someIncludingText(branch.childNodes[last], predicate)) {
if (tree.someIncludingText(root.childNodes[last], predicate)) {
return true;
} // otherwise none of the nodes inside it matched.
// check the node itself
if (predicate(branch.childNodes[last], last)) {
if (predicate(root.childNodes[last], last)) {
return true;
}
last--;
@ -53,6 +55,7 @@ define([], function () {
return false;
};
// FIXME not being used
tree.findSameHierarchy = function (list, ancestor) {
var i = 0;
var success = true;
@ -90,117 +93,74 @@ define([], function () {
return Array.prototype.indexOf.call(el.parentNode.childNodes, el);
};
var siblingCount = tree.siblingCount = function (el) {
return el.parentNodes.childNodes.length;
// not being used internally, but is useful externally
tree.contains = function (el, root) {
return el && root.contains && root.contains(el);
};
var deepestNode = tree.deepestNode = function (el) {
var deepest = el.childNodes.length;
if (!deepest) { // no children
var siblingCount = tree.siblingCount = function (el) {
return el.parentNode.childNodes.length;
};
var childCount = tree.childCount = function (el) {
return el.childNodes.length;
};
var parentsOf = tree.parentsOf = function (el, root) {
var P = [];
var p = el;
while (p !== root) { P.push((p = p.parentNode)); }
return P;
};
/* rightmost and leftmost return the deepest right and left
leaf nodes of a tree
*/
var rightmostNode = tree.rightmostNode = function (el) {
var childNodeCount = childCount(el);
if (!childNodeCount) { // no children
return el; // return the element
} else {
return deepestNode(el.childNodes[deepest - 1]);
return rightmostNode(el.childNodes[childNodeCount - 1]);
}
};
var leftMostNode = tree.leftMostNode = function (el) {
var left = el.childNodes[0];
if (el.childNodes.length) {
return leftMostNode(el.childNodes[0]);
var leftmostNode = tree.leftmostNode = function (el) {
if (childCount(el)) {
return leftmostNode(el.childNodes[0]);
} else {
return el;
}
};
/* previousNode and nextNode traverse child elements of the dom
in the order in which they appear when selected by a cursor.
in particular, these algorithms traverse text nodes, not just tags
*/
var previousNode = tree.previousNode = function (el, root) {
if (!el || el === root) { return null; }
var i = indexOfNode(el);
if (!el.parentNode) { return null; }
if (i === 0) {
if (root && el.parentNode === root.childNodes[0]) { return null; }
return deepestNode(previousNode(el.parentNode));
return rightmostNode(previousNode(el.parentNode));
} else {
return el.parentNode.childNodes[i-1];
return rightmostNode(el.parentNode.childNodes[i-1])
}
};
/* includes text elements */
var nextNode = tree.nextNode = function (el, root) {
if (!el || el === root) {
return null;
}
if (!el || el === root) { return null; }
var i = indexOfNode(el) + 1, // the index of the next node
l = el.parentNode.childNodes.length;
l = siblingCount(el);
if (i === l) { // out of bounds
return leftMostNode(nextNode(el.parentNode, root));
if (el.parentNode === root) { return null; }
return nextNode(el.parentNode, root);
} else {
return el.parentNode.childNodes[i];
return leftmostNode(el.parentNode.childNodes[i], root);
}
};
tree.recoverElement = function (el, root) {
var tags = tree.tagsUntilElement(el, root);
var found = tree.findSameHierarchy(tags, root);
var isSame = found === el;
console.log("found an equivalent node: %s", isSame);
return found;
};
tree.tagsUntilElement = function (el, ancestor) {
var list = [];
tree.someIncludingText(ancestor, function (e, index) {
list.push(e.tagName||e.nodeName);
return e === el;
});
return list;
};
tree.distanceFromEnd = function (el, ancestor) {
var i = 0, success = false;
// FIXME can't be trusted if element is not found.
tree.some(ancestor, function (e, index) {
++i;
return e === el;
});
return i;
};
tree.nthFromEnd = function (n, ancestor) {
var el = false, i = 0;
tree.some(ancestor, function (e) {
if (i > n) {
// terminate
return true;
} else {
if (++i === n) {
el = e;
return true;
} else {
return false;
}
}
});
return el;
};
tree.contains = function (el, ancestor) {
return el && ancestor.contains && ancestor.contains(el);
};
tree.check = function (el, ancestor) {
return tree.nthFromEnd(tree.distanceFromEnd(el, ancestor), ancestor) === el;
};
// TODO see if we can use this
tree.getNext = function (node, parent) {
if (node.firstChild) { return node.nextSibling; }
do {
if(node.nextSibling) { return node.nextSibling; }
node = node.parentNode;
} while (node && node !== parent);
};
return tree;
});