Return early when calculating one-to-one room avatars
Object.keys() is O(n) and is wasted because we only care if the keys are 1 or 2. Use `for .. in` instead and return early if there are >2 keys. Profiling indicates this cuts wasted time from ~74ms to ~32ms for me (who has a large number of rooms with large numbers of people in them).
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1 changed files with 15 additions and 5 deletions
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@ -67,14 +67,24 @@ module.exports = React.createClass({
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},
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getOneToOneAvatar: function(props) {
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var userIds = Object.keys(props.room.currentState.members);
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var mlist = props.room.currentState.members;
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var userIds = [];
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// for .. in optimisation to return early if there are >2 keys
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for (var uid in mlist) {
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if (mlist.hasOwnProperty(uid)) {
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userIds.push(uid);
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}
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if (userIds.length > 2) {
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return null;
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}
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}
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if (userIds.length == 2) {
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var theOtherGuy = null;
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if (props.room.currentState.members[userIds[0]].userId == MatrixClientPeg.get().credentials.userId) {
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theOtherGuy = props.room.currentState.members[userIds[1]];
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if (mlist[userIds[0]].userId == MatrixClientPeg.get().credentials.userId) {
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theOtherGuy = mlist[userIds[1]];
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} else {
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theOtherGuy = props.room.currentState.members[userIds[0]];
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theOtherGuy = mlist[userIds[0]];
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}
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return theOtherGuy.getAvatarUrl(
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MatrixClientPeg.get().getHomeserverUrl(),
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@ -82,7 +92,7 @@ module.exports = React.createClass({
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false
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);
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} else if (userIds.length == 1) {
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return props.room.currentState.members[userIds[0]].getAvatarUrl(
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return mlist[userIds[0]].getAvatarUrl(
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MatrixClientPeg.get().getHomeserverUrl(),
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props.width, props.height, props.resizeMethod,
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false
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